# Line slope calculator 4x-3y=-10

**Straight line given by points A[2; 6] and B[5; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.3333x+3.3333

**Canonical form of the line equation:**4x-3y+10 = 0

**Parametric form of the line equation:**

x = 3t+2

y = 4t+6 ; t ∈ R

**Slope:**m = 1.3333

**Slope angle of line: φ =**53°7'48″ = 0.9273 rad

**X intercept:**x

_{0}= -2.5

**Y intercept:**y

_{0}= q = 3.3333

**Distance line from the origin:**d

_{0}= 2

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; 4)

**Normal vector: n =**(4; -3)

**Midpoint of the segment AB: M =**[3.5; 8]

**Perpendicular Bisector equation:**3x+4y-42.5 = 0

**Vector OA = (2; 6) ; |OA| = 6.3246**

**Vector OB = (5; 10) ; |OB| = 11.1803**

**Scalar product OA .OB = 70**

**Angle ∠ AOB = 8°7'48″ = 0.1419 rad**